PHP日期函数date格式化UNIX时间的方法

本文实例讲述了PHP日期函数date格式化UNIX时间的方法。分享给大家供大家参考。具体分析如下:

日期函数可以根据指定的格式将一个unix时间格式化成想要的文本输出

使用到函数语法如下

  string date (string $Format);  string date (string $Format, int $Time);

下面是演示代码

  <?php  echo "When this page was loaded,n";  echo 'It was then ', date ('r'), "n";  echo 'The currend date was ', date ('F j, Y'), "n";  echo 'The currend date was ', date ('M j, Y'), "n";  echo 'The currend date was ', date ('m/d/y'), "n";  echo 'The currend date was the ', date ('jS of M, Y'), "n";  echo 'The currend time was ', date ('g:i:s A T'), "n";  echo 'The currend time was ', date ('H:i:s O'), "n";  echo date ('Y');  date ('L')?(print ' is'):(print ' is not');  echo " a leap yearn";  echo time ('U'), " seconds had elapsed since January 1, 1970.n";  ?>

输出结果如下

  It was then Sat, 26 Dec 2009 07:09:51 +0000  The currend date was December 26, 2009  The currend date was Dec 26, 2009  The currend date was 12/26/09  The currend date was the 26th of Dec, 2009  The currend time was 7:09:51 AM GMT  The currend time was 07:09:51 +0000  2009 is not a leap year  1261811391 seconds had elapsed since January 1, 1970.

希望本文所述对大家的php程序设计有所帮助。

PHP日期函数date格式化UNIX时间的方法

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